Daily review: Voltage Divider Rules | Ohm’s Law Quiz

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Question 1 of 10

According to Ohm's Law, what is the relationship between current and resistance in a circuit with a constant voltage?

Ohm's Law states I = V/R, meaning current is inversely proportional to resistance when voltage is constant.
Question 2 of 10

In a series circuit with two resistors R1 and R2 connected to a source V, what is the voltage across R1?

The voltage divider rule states the voltage across a specific resistor is the source voltage multiplied by the ratio of that resistor to the total resistance.
Question 3 of 10

If the voltage across a 10-ohm resistor is 20V, what is the current flowing through it?

Using Ohm's Law, I = V / R = 20V / 10? = 2A.
Question 4 of 10

When applying the voltage divider rule, what must be true about the resistors?

The voltage divider rule is specifically derived for resistors connected in series to divide the source voltage.
Question 5 of 10

What happens to the current in a circuit if the resistance is doubled while the voltage remains constant?

Since I = V/R, doubling R results in the current being halved.
Question 6 of 10

A 12V source is connected to a series string of two 2k-ohm resistors. What is the voltage at the midpoint?

With equal resistances, the voltage splits equally across the two resistors: 12V / 2 = 6V.
Question 7 of 10

Which of the following is an incorrect variation of Ohm's Law?

The correct algebraic form is I = V / R, not I = V * R.
Question 8 of 10

If you have a 24V source and two resistors in series, R1 = 100 ohms and R2 = 300 ohms, what is the voltage across R2?

V_R2 = 24 * (300 / (100 + 300)) = 24 * (300 / 400) = 24 * 0.75 = 18V.
Question 9 of 10

What unit is used to measure the ratio of voltage to current?

Resistance (R = V/I) is measured in Ohms (?).
Question 10 of 10

In a voltage divider circuit, what happens to the output voltage if the load resistor connected in parallel to R2 is very small?

Adding a parallel load reduces the total equivalent resistance of that leg, causing the voltage to drop.
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