Daily review: Voltage Divider Rules | Photodiode | Importance of Earthing Rules in Installations Quiz
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10 Questions
Question 1 of 10
In a simple voltage divider circuit with two resistors R1 and R2 in series, what is the formula for the voltage across R2 (V_out)?
The voltage across a resistor in a series string is proportional to its resistance relative to the total circuit resistance.
Question 2 of 10
What is the primary operating mode of a photodiode when used for high-speed light detection applications?
Reverse bias mode reduces junction capacitance, allowing for faster response times in light sensing.
Question 3 of 10
Which of the following is a primary safety purpose of earthing in electrical installations?
Earthing ensures fault current flows to the ground, triggering protective devices like breakers to prevent electric shock.
Question 4 of 10
If you have a 12V source and two equal resistors (1k? each) in a voltage divider, what is the voltage at the center node?
With equal resistors, the voltage splits exactly in half: 12V * (1k / (1k + 1k)) = 6V.
Question 5 of 10
How does incident light affect the current flowing through a reverse-biased photodiode?
Photons generate electron-hole pairs in the depletion region, which increases the reverse current flow (photocurrent).
Question 6 of 10
Which grounding practice helps prevent the accumulation of static charge on equipment enclosures?
Equipment earthing drains static charges to the earth, preventing potential build-up that could damage sensitive components.
Question 7 of 10
In a voltage divider, what happens to V_out if the load resistor added in parallel to R2 has a very low resistance?
The effective resistance of the bottom branch decreases, pulling the output voltage lower than the unloaded divider value.
Question 8 of 10
What is the 'dark current' in a photodiode?
Dark current is the small leakage current that persists in a photodiode even in total darkness.
Question 9 of 10
What is the benefit of using an equipotential bonding strip in an electrical installation?
Equipotential bonding prevents dangerous voltage differences between metal objects during a fault.
Question 10 of 10
Why is the photodiode material usually semiconductor-based?
Semiconductors have band-gaps that allow photons with sufficient energy to promote electrons, creating an electrical signal.
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