Ohm's Law Calculations for Circuit Analysis Quiz
hard
10 Questions
Question 1 of 10
A series circuit has a voltage source of 24V and three resistors: R1 = 2 Ohms, R2 = 3 Ohms, and R3 = 7 Ohms. What is the current flowing through R2?
In a series circuit, current is the same throughout. Total resistance is 12 ohms; current is V/R = 24V/12 Ohms = 2A.
Question 2 of 10
A parallel circuit has three branches. Branch 1 has a 12V source and a 4 Ohm resistor. Branch 2 has a 12V source and a 6 Ohm resistor. Branch 3 has a 12V source and a 3 Ohm resistor. What is the total current supplied by the source?
Calculate current in each branch (3A, 2A, 4A). Total current is the sum of branch currents: 9A.
Question 3 of 10
A 100-watt light bulb operates on a 120V power supply. What is the resistance of the light bulb filament?
Use P=V^2/R. Rearrange: R = V^2/P = 120^2/100 = 144 Ohms.
Question 4 of 10
What is the voltage drop across a 50 Ohm resistor if 0.5 Amperes of current is flowing through it?
Use Ohm's Law: V = I * R = 0.5 A * 50 Ohms = 25V.
Question 5 of 10
A circuit contains a 9V battery and a 330 Ohm resistor. What is the power dissipated by the resistor?
Calculate current (I = V/R = 9/330 A). Then power: P = V*I= 9 * (9/330) ? 0.245 W.
Question 6 of 10
If a resistor dissipates 5 Watts of power with a 10V voltage drop across it, what is the resistance of the resistor?
Use P=V^2/R. Rearrange: R = V^2/P = 10^2/5 = 20 Ohms.
Question 7 of 10
Two resistors, 10 Ohms and 20 Ohms, are connected in series across a 12V source. What is the voltage drop across the 20 Ohm resistor?
Total resistance is 30 Ohms. Current: I = V/R = 12/30 = 0.4A. V = I*R = 0.4A * 20 Ohms = 8V.
Question 8 of 10
A parallel circuit has three resistors with values of 10 Ohms, 20 Ohms and 30 Ohms. The voltage source is 60V. What is the current through the 10 Ohm resistor?
In a parallel circuit, voltage is same across each branch. Current through 10 Ohm resistor: I = V/R = 60V/10 Ohms = 6A.
Question 9 of 10
Calculate the equivalent resistance of two resistors, 4 Ohms and 12 Ohms, connected in parallel.
Use 1/R_eq = 1/R1 + 1/R2. 1/R_eq = 1/4 + 1/12 = 1/3, therefore R_eq = 3 Ohms.
Question 10 of 10
In a simple circuit with a battery and a resistor, if the voltage doubles and the resistance remains constant, what happens to the current?
Ohm's Law: I = V/R. If V doubles and R stays the same, I doubles.
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